Motorola M500 User Manual Page 17

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M500 180 Page 15
The full construction is as follows.
Draw a diameter of the circle AB and name the centre O. Choose a
point P on the circle. Draw a line parallel to AOB through P using the
given construction. Let this meet the circle the second time at Q. Draw AP
and BQ to meet at R. Draw and extend OR to meet the circle at F and G.
By symmetry, OR is perpendicular to AB.
Construct a line through F parallel to AOB and a line through A parallel
to FOG crossing at J. Then JFOA is the required square.
A
B
O
F
G
P
Q
R
J
ADF writes—Observe that the ruler is used only to draw straight lines
through well-defined points. As a couple of readers demonstrated, the con-
struction becomes much easier if it is permitted to use the ruler in an imag-
inative manner. Notice also that significant use is made of the curved part
of the circle-and-its-centre. This is expected. A unit line segment by itself
is not sufficient for constructing the irrational length
2, the diagonal of
the square.
Problem 178.2 and Problem 176.5 (Given a unit line segment, construct
a unit square using only a pair of compasses—see M500 176 28 and p.
25 of this issue) are special cases of a more general result: None of the
traditional ‘Euclidean’ ruler-and-compasses constructions actually require
both instruments.
As suggested above, it seems that we can dispense with the compasses
if there is a unit circle already on the page. This is indeed the case, as was
proved by Jakob Steiner in Die geometrischen Konstruktionen ausgef¨uhrt
mittels der gareden Linie und Eines festen Kreises (Berlin 1833). On the
other hand, L. Mascheroni (La geometria del compasso, Pavia 1797) proved
that Euclidean constructions do not require the ruler if one has access to
a fixed unit line segment. Heinrich Dorrie discusses these two theorems
(as well as 98 others) in 100 Great Problems of Elementary Mathematics
(Dover, New York 1965).
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